prepared URL API
- Vorherrschende Sprache
- Python
- Sterne
- 16.5k
- Forks
- 2.4k
- Ø Merge
- 17 Std. 22 Min.
- Gemergte PRs (30 T.)
- 212
Beschreibung
Is there a way to get prepared URL, which will be used in a query? Something like:
```
req = ClientSession().Request(method='GET', url='http://path.org', data={'a':1, 'b':2})
url = req.prepared_url() -> 'http://path.org?a=1&b=2'
req.headers.update({'auth': auth_fun(url)})
```
I need this for authentication purposes.
Till now I used `requests.Request.prepare().path_url` for the URL and yet sent aiohttp request, but I just found out that sometimes the argument ordering in the output URL will differ between the libraries. Nasty bug.
My first reflex was to try with `ClientRequest` but it requries YARL's URL object (I think?), which is doable I guess, but maybe there's something short and sweet already available.
Can you please help me out?
Beitragsleitfaden
Bewertung
Dieses Issue wurde noch nicht bewertet.