adamerose / adamerose/PandasGUI

Executing code only if the gui is open

Aperta
#217 0 commenti 0 reazioni 0 assegnatari Vedi su GitHub
Lingua principale
Python
Stelle
3.3k
Fork
239
Metriche di merge delle PR
Nessuna PR unita negli ultimi 30g

Descrizione

I'm trying to make a basic script that could open a dataframe in the gui and then update this dataframe every 'x' seconds. However, my best attempt just results in the show() command being executed infinitely with no delay until I kill the script. Here's an example:

```
updateTimer = 5
if __name__ == '__main__':
gui = show(df, settings = {'block': False})

trackTime = time.time()

while gui:
if (time.time() - trackTime >= updateTimer):
df = pymongo.DataFrame(RedBoard.find())
df = df[df['Date_Time'].notnull()]
gui.store.remove_dataframe('df')
gui.store.add_dataframe(df, 'df')
```
is there something in the library that would allow me to directly check if the window is open? If not, what would be my best course of action to only execute the code in the `while` loop when the gui is open?

Guida per i contributori

Nessuna guida per i contributori indicizzata per questo repository

Valutazione

Questa issue non è ancora stata valutata.

Ricevi le nuove issue nella tua casella

Un breve riepilogo di issue GitHub adatte ai principianti.