adambard / adambard/learnxinyminutes-docs
[rust/en] clarify the difference between `impl<T> Foo<T>` and `impl Foo<T>`
未关闭
quickfix
- 主要语言
- Markdown
- 星标
- 12.3k
- 派生
- 3.7k
- 平均合并
- 13 小时 10 分钟
- 30 天内合并 PR
- 6
描述
This was confusing to me. At first glance, the first `T` just looks redundant because `Foo` is already
polymorphic. I'd add a note saying that the first `T` is necessary to indicate that `T` in `Foo` here
is not a concrete type, but a type parameter. Or, perhaps add an example where `T` is concrete, then `impl Foo` will get accepted.
贡献指南
评估
这个 Issue 还没有评估数据。