Investigate order()-based approach to frollmax
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Assessment
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Newbie friendliness
- 25/100
- Issue type
- Refactor
- Clarity
- Needs clarification
- Activity status
- Stale
- Tech stack
- r
- Domain
- performance
Research direction
Start with the frollmax implementation and the discussion linked in the issue. Evaluate the proposed order()-based approach against the existing algorithm, focusing on sorting costs and worst-case behavior; done means producing a reasoned assessment of whether it should be pursued.
Written by the indexing model from the issue text.
Description
Another algorithm that comes to mind and avoids the need to double-pass the vector ever, maybe you've seen it implemented elsewhere?
- Compute
o=order(x) - Set output to the value where
x[o[1]]foro[1], ..., o[1]+k-1 - Find the next
o[i]outsideo[1], ..., o[1]+k-1 - Repeat until
ois "empty"
Maybe it will perform poorly since it requires sorting --> best case it's O(n log n), whereas IINM this algorithm is best case O(n) (?)
But maybe it will do better in the worst case?
Originally posted by @MichaelChirico in https://github.com/Rdatatable/data.table/pull/5889#discussion_r1447122993
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