aggregate same variable as groupby on-the-fly expression won't make it length 1
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Assessment
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Newbie friendliness
- 35/100
Research direction
Start with the two reproducible data.table expressions in the issue and compare the grouped results. Read the FAQ section “Inside each group, why are the group variables length-1?” and trace the relevant grouping behavior. Done means grouping by the on-the-fly factor expression produces the same TotalA value as grouping by SomeNumberA.
Written by the indexing model from the issue text.
Description
Reported by @geofflazzarini in https://github.com/Rdatatable/data.table/issues/3103#issuecomment-439286088
There should be no difference in TotalA column in results
library(data.table)
dt = data.table(SomeNumberA=c(1,1,1),SomeNumberB=c(1,1,1))
dt[, .(.N, TotalA=sum(SomeNumberA), TotalB=sum(SomeNumberB)), by=SomeNumberA]
# SomeNumberA N TotalA TotalB
# <num> <int> <num> <num>
#1: 1 3 1 3
dt[, .(.N, TotalA=sum(SomeNumberA), TotalB=sum(SomeNumberB)), by=as.factor(SomeNumberA)]
# as.factor N TotalA TotalB
# <fctr> <int> <num> <num>
#1: 1 3 3 3
This might be tricky because of "Inside each group, why are the group variables length-1?" in FAQ.
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