JuliaPy / JuliaPy/PythonCall.jl

`DataFrame(::PyPandasDataFrame)` converts date & datetime to bytes

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#293 18 comentarios 0 reacciones 0 asignados Ver en GitHub
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Descripción

When doing some work involving dataframes in python via PythonCall, it seems like `DataFrame(PyTable(p))` where `p` is a pandas data table converts the date and datetime columns into byte vectors. Is this issue related to the issue #265 with milliseconds vs microseconds, or due to a missing part of the `DataFrame(::PyPandasDataFrame)` implementation?

Here are a few minimal examples, in a conda environment with pandas.

```
using PythonCall
using Dates
using DataFrames

a = DataFrame(x = [now()]) # julia dataframe
b = pytable(a) # pandas dataframe
c = PyTable(b) # PyPandasDataFrame
d = DataFrame(c) # julia dataframe again
```
This results in:
```
julia> c
1×1 PyPandasDataFrame
x
0 2023-04-13 14:36:13.939

julia> d
1×1 DataFrame
Row │ x
│ PyArray…
─────┼───────────────────────────────────
1 │ UInt8[0xc0, 0x62, 0x31, 0x8c, 0x…
```
The same thing happens when initially defining `b` as a pandas dataframe, so the microsecond issue in #265 seems to not be the problem?
```
julia> b = pd.DataFrame([[dt.datetime.now()]])
Python DataFrame:
0
0 2023-04-13 14:46:57.940077

julia> c = PyTable(b)
1×1 PyPandasDataFrame
0
0 2023-04-13 14:46:57.940077

julia> d = DataFrame(c)
1×1 DataFrame
Row │ 0
│ PyArray…
─────┼───────────────────────────────────
1 │ UInt8[0xc8, 0xf9, 0xa5, 0x7d, 0x…
```

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