JuliaPy / JuliaPy/PyCall.jl

Support Py_LIMITED_API in separate package as a dependency to PyCall.jl

Abierto
#714 4 comentarios 2 reacciones 0 asignados Ver en GitHub
Lenguaje dominante
Julia
Estrellas
1.5k
Forks
186
Métricas de merge de PR
Sin PR fusionados en 30 d

Descripción

The Python C ABI/API has stability guarantees for a limited number of structs and functions.

https://www.python.org/dev/peps/pep-0384/

It'd be nice to support this as a separate package and use that package as a dependency in PyCall.jl. This separate package can implement the Py_LIMITED_API structs and functions without invoking the Python interpreter.

A (very early) prototype is located here:

https://github.com/kdheepak/Python.jl/blob/33b98177b0e624588a3f46ccfa96b317d57f1201/src/Python.jl

The motivation for this is so that we can build a shared object from a Julia file using [PackageCompiler.jl](https://github.com/JuliaLang/PackageCompiler.jl) that is also a Python module. See screenshot below as an [example](https://github.com/JuliaLang/PackageCompiler.jl/blob/f40fb987c7e5f3d6c6ad9245f957af90b78bf575/hello.jl):

Screen Shot 2019-09-24 at 11 02 34 PM

No linking to the Python library occurs at compile time and the Python module does not embed a Python interpreter; it is a pure Julia shared library. This allows one to create a Python module without having Python installed and the structs and functions described in the Py_LIMITED_API would be sufficient to make this work.

Taking this a step further, we could allow for something like the following in the future (See https://github.com/yglukhov/nimpy and https://github.com/PyO3/PyO3 for similar projects in Nim and Rust):

**Write Julia code**

```julia
# hello.jl
using Python

@pycallable function hello(name::String)::Cvoid
println("Hello $name!")
end
```

**Compile**

```bash
$ julia --project juliac.jl -vasij `pwd`/hello.jl > /dev/null
```

**Run in Python**

```bash
$ ipython
Python 3.7.3 (default, Mar 27 2019, 16:54:48)
Type 'copyright', 'credits' or 'license' for more information
IPython 7.8.0 -- An enhanced Interactive Python. Type '?' for help.

In [1]: import hello

In [2]: hello.hello("John")
Hello John!

In [3]:
```

My understanding is that this would pose some challenges with the current setup in PyCall.jl since PyCall.jl initializes a interpreter in [`__init__`](https://github.com/JuliaPy/PyCall.jl/blob/9f4387535936f275e3582ebdc87cc2ef1f210030/src/pyinit.jl#L128) and when PackageCompiler runs, the references to that interpreter are embedded in the shared library.

Comments?

Guía de contribución

No hay ninguna guía de contribución indexada para este repositorio

Evaluación

Este issue todavía no se ha evaluado.

Recibe los nuevos issues en tu correo

Un resumen breve de issues de GitHub para principiantes.