JuliaPy / JuliaPy/PyCall.jl

zero-arg call to Python `super()` not working

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Beschreibung

As the title says, the zero-arg version of `super()` doesn't work,

```julia
julia> @pydef type Foo
__str__(self) = pybuiltin(:super)()[:__str__]()
end
PyObject

julia> Foo()[:__str__]()
ERROR: PyError (ccall(@pysym(:PyObject_Call), PyPtr, (PyPtr, PyPtr, PyPtr), o, arg, C_NULL))
RuntimeError('super(): no arguments',)
File "PyCall", line 1, in

Stacktrace:
[1] pyerr_check at /home/marius/.julia/v0.6/PyCall/src/exception.jl:56 [inlined]
[2] pyerr_check at /home/marius/.julia/v0.6/PyCall/src/exception.jl:61 [inlined]
[3] macro expansion at /home/marius/.julia/v0.6/PyCall/src/exception.jl:81 [inlined]
[4] #_pycall#66(::Array{Any,1}, ::Function, ::PyCall.PyObject) at /home/marius/.julia/v0.6/PyCall/src/PyCall.jl:620
[5] #pycall#70(::Array{Any,1}, ::Function, ::PyCall.PyObject, ::Type{PyCall.PyAny}) at /home/marius/.julia/v0.6/PyCall/src/PyCall.jl:642
[6] #call#71 at /home/marius/.julia/v0.6/PyCall/src/PyCall.jl:645 [inlined]
[7] (::PyCall.PyObject)() at /home/marius/.julia/v0.6/PyCall/src/PyCall.jl:645
```

although the manual version is fine,

```julia
julia> @pydef type Bar
__str__(self) = pybuiltin(:super)(Bar,self)[:__str__]()
end
PyObject

julia> Bar()[:__str__]()
""
```

I'm guessing what's happening is described by [this](https://stackoverflow.com/a/39313448/1078529) answer,

> The zero-argument form of super requires that the method containing it have an explicit (i.e., non-varargs) first argument

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