Question regarding Object Communication video 7.7

Hello! I have a question in regards to the final result of the object communication code found in your program at the end of the 7.7 video. The code reads like this:

`for (b of bubbles) {`
` b.show();`
` b.move();`
` let overlapping = false;`
` for (other of bubbles) {`
` if (b !== other && b.intersects(other)) {`
` overlapping = true;`
` }`
` }`
` if (overlapping) {`
` b.changeColor(255);`
` } else {`
` b.changeColor(0);`
` }`
`}`

Please forgive me if I cannot ask this question properly: How would you, in this example, reference the *other* object within the *b* object's code? For example...

Let's say I want to draw a line that is 500 pixels long from the x and y of the *b* object at a random angle outwards every frame. Now, if an *other* object is "within range", so within 500 pixels of the *b* object, then draw the line from the x and y of the *b* object to the x and y of the *other* object (now less than 500 pixels long).

In the case above, I would need to pull the x and y coordinates of the *b* object and the *other* object within the same scope. The problem that I am having is that the if statement regarding overlapping being true or false is removed from the scope of the `for (other of bubbles)` loop, and as explained in the video, is necessary to avoid the problem of only-last-object interaction. So how could you remove the *other* object from scope while also running through the for loop every frame, while simultaneously avoiding the only-last-interaction problem?

Thank you!

Die Nutzlast verweist auf das Video 7.7 zu Object Communication und den dort gezeigten finalen Code; beginne mit der Überprüfung dieses Beispiels und der Scope-Regeln der Frage. Erledigt bedeutet, eine dokumentierte Erklärung bereitzustellen, die den Zugriff auf beide Objekte behandelt, ohne das Interaktionsproblem mit nur dem letzten Objekt wieder einzuführen.

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