getFileCharsetSimple : 简单获取文件编码格式 存在问题

## 描述 Bug

FileUtils.java 中 getFileCharsetSimple : 简单获取文件编码格式 存在判断文件编码格式不准的问题

我是参考的
`public class CharsetUtil {

/**
* 如果文件是utf8编码返回true,反之false
* @param file
* @return
*/
public static Boolean isUtf8(File file) {
boolean isUtf8 = true;
byte[] buffer = readByteArrayData(file);
int end = buffer.length;
for (int i = 0; i < end; i++) {
byte temp = buffer[i];
if ((temp & 0x80) == 0) {// 0xxxxxxx
continue;
} else if ((temp & 0xC0) == 0xC0 && (temp & 0x20) == 0) {// 110xxxxx 10xxxxxx
if (i + 1 < end && (buffer[i + 1] & 0x80) == 0x80 && (buffer[i + 1] & 0x40) == 0) {
i = i + 1;
continue;
}
} else if ((temp & 0xE0) == 0xE0 && (temp & 0x10) == 0) {// 1110xxxx 10xxxxxx 10xxxxxx
if (i + 2 < end && (buffer[i + 1] & 0x80) == 0x80 && (buffer[i + 1] & 0x40) == 0
&& (buffer[i + 2] & 0x80) == 0x80 && (buffer[i + 2] & 0x40) == 0) {
i = i + 2;
continue;
}
} else if ((temp & 0xF0) == 0xF0 && (temp & 0x08) == 0) {// 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx
if (i + 3 < end && (buffer[i + 1] & 0x80) == 0x80 && (buffer[i + 1] & 0x40) == 0
&& (buffer[i + 2] & 0x80) == 0x80 && (buffer[i + 2] & 0x40) == 0
&& (buffer[i + 3] & 0x80) == 0x80 && (buffer[i + 3] & 0x40) == 0) {
i = i + 3;
continue;
}
}
isUtf8 = false;
break;
}
return isUtf8;
}

/**
* 如果文件是gbk编码或者gb2312返回true,反之false
* @param file
* @return
*/
public static Boolean isGbk(File file) {
boolean isGbk = true;
byte[] buffer = readByteArrayData(file);
int end = buffer.length;
for (int i = 0; i < end; i++) {
byte temp = buffer[i];
if ((temp & 0x80) == 0) {
continue;// B0A1-F7FE//A1A1-A9FE
} else if ((Byte.toUnsignedInt(temp) < 0xAA && Byte.toUnsignedInt(temp) > 0xA0)
|| (Byte.toUnsignedInt(temp) < 0xF8 && Byte.toUnsignedInt(temp) > 0xAF)) {
if (i + 1 < end) {
if (Byte.toUnsignedInt(buffer[i + 1]) < 0xFF && Byte.toUnsignedInt(buffer[i + 1]) > 0xA0
&& Byte.toUnsignedInt(buffer[i + 1]) != 0x7F) {
i = i + 1;
continue;
}
} // 8140-A0FE
} else if (Byte.toUnsignedInt(temp) < 0xA1 && Byte.toUnsignedInt(temp) > 0x80) {
if (i + 1 < end) {
if (Byte.toUnsignedInt(buffer[i + 1]) < 0xFF && Byte.toUnsignedInt(buffer[i + 1]) > 0x3F
&& Byte.toUnsignedInt(buffer[i + 1]) != 0x7F) {
i = i + 1;
continue;
}
} // AA40-FEA0//A840-A9A0
} else if ((Byte.toUnsignedInt(temp) < 0xFF && Byte.toUnsignedInt(temp) > 0xA9)
|| (Byte.toUnsignedInt(temp) < 0xAA && Byte.toUnsignedInt(temp) > 0xA7)) {
if (i + 1 < end) {
if (Byte.toUnsignedInt(buffer[i + 1]) < 0xA1 && Byte.toUnsignedInt(buffer[i + 1]) > 0x3F
&& Byte.toUnsignedInt(buffer[i + 1]) != 0x7F) {
i = i + 1;
continue;
}
}
}
isGbk = false;
break;
}
return isGbk;
}

/**
* 从文件中直接读取字节
* @param file
* @return
*/
public static byte[] readByteArrayData(File file) {
byte[] rebyte = null;
BufferedInputStream bis;
ByteArrayOutputStream output;
try {
bis = new BufferedInputStream(new FileInputStream(file));
output = new ByteArrayOutputStream();
byte[] byt = new byte[1024 * 4];
int len;
try {
while ((len = bis.read(byt)) != -1) {
if (len < 1024 * 4) {
output.write(byt, 0, len);
} else
output.write(byt);
}
} catch (IOException e) {
e.printStackTrace();
}
rebyte = output.toByteArray();
if (bis != null) {
bis.close();
}
if (output != null) {
output.close();
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}

return rebyte;
}

}`
这个方法目前是准确的

我的运行情况
` charsetName = FileUtils.getFileCharsetSimple(dictPath);
boolean isUtf8 = CharsetUtils.isUtf8(FileUtils.getFileByPath(dictPath));
boolean isGbk = CharsetUtils.isGbk(FileUtils.getFileByPath(dictPath));
LogUtils.i("charsetName:" + charsetName + "\nisUtf8:" + isUtf8 + "\nisGbk:" + isGbk);`
首先放入GBK文件
charsetName:UTF-8
isUtf8:false
isGbk:true
再次放入UTF-8文件
charsetName:UTF-8
isUtf8:true
isGbk:false
所以我认为这个有问题....我暂时没看您写的源码