17070047 / 17070047/CodeStructureCourse
解宇飞
- 主要语言
- C++
- 星标
- 16
- 派生
- 2
- PR 合并指标
- 30 天内没有已合并 PR
描述
```c
#include
using namespace std;
const int maxn = 10000 + 10;
struct Node
{
int department;//院号
int number;//借书证卡号
char name[maxn];//姓名
char student_id[maxn];//学号
};
Node a[maxn];
void quicksort(Node a[], int left, int right)//按照卡号进行排名
{
int i, j;
if (left >= right)
return;
i = left, j = right;
a[0] = a[i];
while (i != j)
{
while (a[j].number > a[0].number && i < j)
--j;
if (i < j)
{
a[i] = a[j];
i++;
}
while (a[i].number < a[0].number && i < j)
++i;
if (i < j)
{
a[j] = a[i];
j--;
}
}
a[i] = a[0];
quicksort(a, left, i - 1);
quicksort(a, i + 1, right);
}
void bin_search(Node a[], int n, int x)
{
int left = 1, right = n;
int ans = 0;
while (left <= right)
{
int mid = (left + right) / 2;
if (a[mid].department == x)
{
ans = mid;
break;
}
else if (a[mid].department < x)
{
left = mid + 1;
}
else
{
right = mid - 1;
}
}
if (!ans)
{
printf("没找到\n");
}
else
{
int start = ans, ends = ans;
while (a[start].department == x)
start--;
while (a[ends].department == x)
ends++;
printf("%d院的信息为:\n", x);
for (int i = start + 1; i < ends; i++)
{
printf("%d %d %s %s\n", a[i].department, a[i].number, a[i].name, a[i].student_id);
}
}
}
int main()
{
int n;
int i;
printf("请输入信息系统学生的个数:\n");
scanf("%d", &n);
printf("请输入学生学院号、卡号、姓名、学号:\n");
for (i = 1; i <= n; i++)
{
scanf("%d%d%s%s", &(a[i].department), &a[i].number, &a[i].name, &a[i].student_id);
}
quicksort(a, 1, n);
printf("按照卡号顺序输出学生信息:\n");
for (i = 1; i <= n; i++)
{
printf("%d %d %s %s\n", a[i].department, a[i].number, a[i].name, a[i].student_id);
}
int x;
printf("请输入要查找的学院号:\n");
scanf("%d", &x);
bin_search(a, n, x);
return 0;
}
```

贡献指南
这个仓库没有索引到贡献指南
调研方向
The issue contains a C program with a quicksort and binary search for student records. The problem is not described; the image link is broken. To start, examine the code for logical errors, such as off-by-one indexing (arrays start at 1) or incorrect binary search on unsorted department field. Run the program with sample input to see if it crashes or produces wrong output. Check the repository for similar programs or assignment instructions to understand the expected behavior.
由索引模型根据 Issue 内容生成。
评估
- 技术栈
- c, cpp
- 领域
- cli
- Issue 类型
- 缺陷
- 难度
- 3/5
- 预计耗时
- 1-2 天
- 活跃度
- 停滞
- 描述清晰度
- 需要澄清
- 新手友好度
- 20/100