17070047 / 17070047/CodeStructureCourse
丁晓凡
- 主要語言
- C++
- 星號
- 16
- 分支
- 2
- PR 合併指標
- 30 天內沒有已合併 PR
描述
``` c
#include "stdafx.h"
#include"stdio.h"
#include"stdlib.h"
#include"string.h"
#define m 20
#define max 100
typedef struct studentnode{
char cardnum[m];
char name[m];
char classnum[m];
char college[m];
}node;
typedef struct{
node r[max+1];
int length;
}table;
void sort(table *tab,int left,int right)
{
int i,j;
if(leftr[0]=tab->r[i];
do
{ while(strcmp(tab->r[j].cardnum,tab->r[0].cardnum)==1&&ir[i]=tab->r[j];
i++;
}
while(strcmp(tab->r[i].cardnum,tab->r[0].cardnum)==-1&&ir[j]=tab->r[i];j--;}
}while(i!=j);
tab->r[i]=tab->r[0];
sort(tab,left,i-1);
sort(tab,i+1,right);
}
}
void creat(table *tab)
{
int i,j,k;
printf("请输入结点个数:\n");
scanf("%d",&tab->length);
tab->length++;
getchar();
for(i=1;ilength;i++)
{
printf("请输入卡号:\n");
gets(tab->r[i].cardnum);
printf("请输入名字:\n");
gets(tab->r[i].name);
printf("请输入班号:\n");
gets(tab->r[i].classnum);
printf("请输入系别:\n");
gets(tab->r[i].college);
printf("\n");
}
printf("创建完成\n");
}
void find(table *tab)
{
int i,j;
char object[m];
printf("请输入你要查找的系别:\n");
gets(object);
for(i=1;ilength;i++)
{ if(strcmp(object,tab->r[i].college)==0)
{ puts(tab->r[i].cardnum);
puts(tab->r[i].name); puts(tab->r[i].classnum); puts(tab->r[i].college);
printf("\n");
}
}
}
void display(table *tab)
{
int i;
for(i=1;ilength;i++)
{
puts(tab->r[i].cardnum);
puts(tab->r[i].name);
puts(tab->r[i].classnum);
puts(tab->r[i].college);
printf("\n");
}
}
int main()
{
int i;
table *tab;
tab=(table *)malloc(sizeof(table));
creat(tab);
sort(tab,1,tab->length-1);
display(tab);
while(scanf("%d",&i)!=EOF)
{
getchar();
find(tab);
}
return 0;
}
```

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研究方向
The issue contains a C program with a student record management system. The code includes sorting, creation, display, and find functions. The image link is broken. A newcomer would need to understand the intended bug or improvement, but the issue lacks any description of what needs to be fixed. Start by examining the code for logical errors, memory leaks, or unsafe functions like gets(). Run the program to see if it compiles and behaves as expected. Determine what 'done' looks like by clarifying with the maintainer.
由索引模型根據 Issue 內容生成。
評估
- 技術堆疊
- c
- 領域
- cli
- Issue 類型
- 缺陷
- 難度
- 4/5
- 預估耗時
- 3-5 天
- 活躍度
- 停滯
- 描述清晰度
- 需要釐清
- 新手友好度
- 10/100