bug: declaration of function pointer not handling correctly functions without arguments

Did you check existing issues?

• I have read all the tree-sitter docs if it relates to using the parser
• I have searched the existing issues of tree-sitter-cpp

Tree-Sitter CLI Version, if relevant (output of tree-sitter --version)

No response

Describe the bug

Function declarator without any parameters is not parsed correctly in tree-sitter-cpp:

void (*func_t)() = NULL;

Output from the playground:

translation_unit [0, 0] - [6, 0]
  expression_statement [0, 0] - [0, 24]
    assignment_expression [0, 0] - [0, 23]
      left: call_expression [0, 0] - [0, 16]
        function: call_expression [0, 0] - [0, 14]
          function: primitive_type [0, 0] - [0, 4]
          arguments: argument_list [0, 5] - [0, 14]
            pointer_expression [0, 6] - [0, 13]
              argument: identifier [0, 7] - [0, 13]
        arguments: argument_list [0, 14] - [0, 16]
      right: null [0, 19] - [0, 23]

The parser for some reason treats it as an assignment with call expression as the left side.

While tree-sitter-c parses it correctly:

translation_unit [0, 0] - [6, 0]
  declaration [0, 0] - [0, 24]
    type: primitive_type [0, 0] - [0, 4]
    declarator: init_declarator [0, 5] - [0, 23]
      declarator: function_declarator [0, 5] - [0, 16]
        declarator: parenthesized_declarator [0, 5] - [0, 14]
          pointer_declarator [0, 6] - [0, 13]
            declarator: identifier [0, 7] - [0, 13]
        parameters: parameter_list [0, 14] - [0, 16]
      value: null [0, 19] - [0, 23]

Steps To Reproduce/Bad Parse Tree

translation_unit [0, 0] - [6, 0]
  expression_statement [0, 0] - [0, 24]
    assignment_expression [0, 0] - [0, 23]
      left: call_expression [0, 0] - [0, 16]
        function: call_expression [0, 0] - [0, 14]
          function: primitive_type [0, 0] - [0, 4]
          arguments: argument_list [0, 5] - [0, 14]
            pointer_expression [0, 6] - [0, 13]
              argument: identifier [0, 7] - [0, 13]
        arguments: argument_list [0, 14] - [0, 16]
      right: null [0, 19] - [0, 23]

Expected Behavior/Parse Tree

translation_unit [0, 0] - [6, 0]
  declaration [0, 0] - [0, 24]
    type: primitive_type [0, 0] - [0, 4]
    declarator: init_declarator [0, 5] - [0, 23]
      declarator: function_declarator [0, 5] - [0, 16]
        declarator: parenthesized_declarator [0, 5] - [0, 14]
          pointer_declarator [0, 6] - [0, 13]
            declarator: identifier [0, 7] - [0, 13]
        parameters: parameter_list [0, 14] - [0, 16]
      value: null [0, 19] - [0, 23]

Repro

void (*func_t)() = NULL;

Reproduce void (*func_t)() = NULL; in the tree-sitter-cpp playground and inspect the declarator grammar entry points that produce the expression tree. Compare the result with tree-sitter-c's parse tree; done means the C++ grammar produces a declaration with a function declarator, parenthesized pointer declarator, empty parameter list, and initializer.