tensorflow / tensorflow/tensorflow
tf.keras.ops.numpy.sinc returns NaN gradient at zero where derivative should be zero
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Since Sep 16, 2026.
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Description
Issue type
Bug
Have you reproduced the bug with TensorFlow Nightly?
Yes
Source
source
TensorFlow version
tf 2.21.0, also reproduced on tf 2.22.0-dev20260904
Custom code
Yes
OS platform and distribution
Linux Ubuntu 22.04
Mobile device
No response
Python version
Python 3.13.5
Bazel version
No response
GCC/compiler version
No response
CUDA/cuDNN version
No response
GPU model and memory
No response
Current behavior?
tf.keras.ops.numpy.sinc returns nan for the first derivative at a point where the normalized sinc function has a smooth extension and the derivative should be finite.
In the reproducer below, the function evaluates tf.keras.ops.numpy.sinc(2 * t + 1) at t = -0.5, so the argument to sinc is exactly zero. The forward value is correctly returned as 1.0. However, TensorFlow autodiff returns nan for the derivative with respect to t.
The expected derivative is 0.0, including the chain rule through 2 * t + 1.
Expected behavior?
The first derivative of tf.keras.ops.numpy.sinc(2 * t + 1) at t = -0.5 should be 0.0, not nan.
Standalone code to reproduce the issue
import os
os.environ["CUDA_VISIBLE_DEVICES"] = ""
os.environ["OMP_NUM_THREADS"] = "1"
os.environ["TF_NUM_INTRAOP_THREADS"] = "1"
os.environ["TF_NUM_INTEROP_THREADS"] = "1"
import tensorflow as tf
def target(t):
return tf.keras.ops.numpy.sinc(2 * t + 1)
x = tf.constant(-0.5, dtype=tf.float64)
with tf.GradientTape() as tape:
tape.watch(x)
y = target(x)
actual = tape.gradient(y, x)
expected = 0.0
print("forward:", y.numpy())
print("actual:", actual.numpy())
print("expected:", expected)
if tf.math.is_nan(actual):
print("BUG REPRODUCED: tf.keras.ops.numpy.sinc returns NaN gradient at zero")
else:
print("not reproduced")
Relevant log output
forward: 1.0
actual: nan
expected: 0.0
BUG REPRODUCED: tf.keras.ops.numpy.sinc returns NaN gradient at zero
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