OpenAPI 3.1.0 definition parser result drops the license identifier

I used following code snippet to parse the OpenAPI definition and prettyprint it to a json value. But it seems like that the license.identifier is dropped out from the resulting JSON.

Swagger parser 2.1.20

       String openApiFilePath = "<Path>/Petstore-3.1.0.yaml"; // Replace this with the path to your OpenAPI 3.1 specification file
        // Create a new instance of OpenAPIV3Parser
        OpenAPIV3Parser openAPIParser = new OpenAPIV3Parser();

        // Parse the OpenAPI specification
        SwaggerParseResult parseResult = openAPIParser.readLocation(openApiFilePath, null, null);
        String parser = Json.pretty(parseResult.getOpenAPI());

Sample openAPI spec

openapi: 3.1.0
info:
  title: Sample API
  version: 1.0.0
  description: This is a sample API specification with license identifier.
  license:
    name: Apache 2.0
    identifier: Apache-2.0
  contact:
    name: API Support
    email: support@example.com
    url: https://www.example.com/support
servers:
  - url: https://api.example.com/v1
paths:
  /users:
    get:
      summary: Retrieves a list of users
      responses:
        '200':
          description: A list of users
          content:
            application/json:
              schema:
                type: array
                items:
                  type: object
                  properties:
                    id:
                      type: integer
                      description: The user's ID
                    username:
                      type: string
                      description: The user's username

Start with OpenAPIV3Parser.readLocation and the conversion represented by Json.pretty(parseResult.getOpenAPI()), using the supplied OpenAPI 3.1.0 YAML as the reproduction case. Trace how info.license.identifier is parsed and serialized, then verify that the identifier remains in the resulting JSON.