[Swift] Get Status code from error

Description

I wasn't able to get the status code after making a request. My approach was:

let request = UserdetailcontrollerAPI.createUsingPOST2WithRequestBuilder(userInfo: userInfo);
      request.execute {response, error in
            if(error != nil){
                let err = error as! ErrorResponse
                print(err)
                
                switch(error!){
                    case (409,_,_): print("409");
                }
}

Since error is of type Error? I get a "Tuple pattern cannot match values of the non-tuple type: Error"

Swagger-codegen version

I am using the current master branch of swagger 2.0. (Code is generated from a spring server.)

Swagger declaration file content or url

swagger: '2.0'
info:
  description: Api Documentation
  version: '1.0'
  title: Api Documentation
  termsOfService: 'urn:tos'
  contact: {}
  license:
    name: Apache 2.0
    url: 'http://www.apache.org/licenses/LICENSE-2.0'
host: 'localhost:8080'
basePath: /   

...

Command line used for generation

java -jar swagger-codegen-cli.jar generate -i project.json -l swift3 -o ../project_swagger

Steps to reproduce

Related issues

Suggest a Fix

I needed this immediately so I changed the type of ErrorResponse to in Models.mustache. I don't understand the idea of the original code anyhow. Maybe someone can explain it?

public typealias ErrorResponse = (Int, Data?, Error?);

/*
public enum ErrorResponse : Error {
    case Error(Int, Data?, Error)
}
*/

Start with the swift3 generation command and inspect Models.mustache, especially the ErrorResponse definition used by the generated request callback. Regenerate the client from the supplied Swagger definition and verify that callers can obtain the HTTP status code from an error without the tuple-pattern failure.