Day04 资料2中的for in 嵌套循环看不懂了，不知道解决思路或是卡在哪里了

for n in range(2, 10):
     for x in range(2, n):
         if n % x == 0:
             print(n, 'equals', x, '*', n//x)
             break
     else:
         # loop fell through without finding a factor
         print(n, 'is a prime number')

看不懂这个嵌套循环了，程序第一次扫描的时候，n%x==0，n等于2，x等于2。2%2的余数等于0。那应该显示print(n, 'is a prime number')这段，

下次循环，怎么会跳出来，到 else:这段呢？n=3 x=2 余数不等于0，显示print(n, 'equals', x, '*', n//x)。n=3 x=3 余数等于0，显示print(n, 'is a prime number')这段

下次循环n=4 x=2 余数不等于0，显示print(n, 'equals', x, '*', n//x)。n=4 x=3 余数不等于0，显示print(n, 'is a prime number')这段 n=4 x=4 余数等于0，显示print(n, 'is a prime number')这段
晕了

Start by locating the Day04 资料2 material and reviewing the embedded Python example. Clarify the nested loop and its loop-else behavior in the material, with a step-by-step explanation that resolves the reported confusion and makes the expected output understandable.