selfteaching / selfteaching/selfteaching-python-camp
Day04 用while循环加条件去除偶数的问题
Open
Nobody has claimed this yet.
- Dominant language
- Python
- Stars
- 151
- Forks
- 875
- PR merge metrics
- No merged PRs in 30d
Description
f = 1
while f <= 9:
h = 1
while h < f + 1:
if f%2==0:
break
print(f, "*", h, '=', f*h, sep='', end='\t')
h += 1
print()
f += 1
上面是代码
下面是输出结果
@@但是结果当中有空行，自己百度没解决，，
1*1=1
3*1=3 3*2=6 3*3=9
5*1=5 5*2=10 5*3=15 5*4=20 5*5=25
7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49
9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81
Contributor guide
No contributing guide indexed for this repository
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
Run the Python snippet and inspect the control flow around the inner while loop, the break, and the following print() call. Done means the even-number rows are omitted without producing unintended blank lines, while the odd-number multiplication output remains.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- python
- Domain
- cli
- Issue type
- Bug
- Difficulty
- 2/5
- Estimated time
- 1-3 hours
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 35/100