scrapinghub / scrapinghub/dateparser
QUESTION: parameter or method to print the code format of the date
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Description
Is there a parameter or method to print the code format string that matches the parsed date?
For example, in the following code:
from datetime import datetime
now = datetime.now()
date_time = now.strftime("%m/%d/%Y, %H:%M:%S")
print("date and time:",date_time)
You will get:
date and time: 12/21/2021, 22:08:06
So with this code:
dateparser.parse(date_time)
You will get:
datetime.datetime(2021, 12, 21, 22, 08, 06)
Is there a way to run something like this?:
dateparser.get_date_pattern(date_time)
And as a result:
"%m/%d/%Y, %H:%M:%S"
I saw a similar question in Stack Overflow: https://stackoverflow.com/q/33986096/6315428
The purpose? Generate synthetic data for privacy protection, looking to express dates in the same original format, replacing the value with a different one.
Contributor guide
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
Start by reviewing the existing dateparser.parse behavior and the datetime.strftime example in the issue. Determine whether the parsed input preserves enough information to recover the original format string, and define what dateparser.get_date_pattern(date_time) should return for the shown example. Done means the behavior and supported cases are documented and covered by tests.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- python
- Domain
- backend
- Issue type
- Feature
- Difficulty
- 5/5
- Estimated time
- Over a week
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 35/100