Memory order like another array

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#1,072 2 comments 0 reactions 0 assignees View on GitHub

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Assessment

Difficulty
4/5
Estimated time
3-5 days
Newbie friendliness
35/100
Issue type
Feature
Clarity
Mostly clear
Activity status
Stale
Tech stack
rust
Domain
data

Research direction

Start by reading the Array3::from_elem, is_standard_layout(), dim(), clone(), and f() entry points shown in the issue. Trace how array layout is represented and determine the expected behavior for a new array with different dimensions. Done means the intended layout-preserving API is defined, implemented, and tested for both standard and non-standard layouts.

Written by the indexing model from the issue text.

Description

enhancement good first issue

One of my function needs to create a new array with the same order as the input. I know I can use clone() when both arrays have the same dimension, but when it's not the case, it's more complex.

fn binary_dilation(mask: &Array3<bool>) -> Array3<bool> {
    let (width, height, depth) = mask.dim();
    let dim = (width + etc., ...);
    let mut new_mask = if mask.is_standard_layout() {
        Array3::from_elem(dim, false)
    } else {
        Array3::from_elem(dim.f(), false)
    };
    // Do something
}

Is there a one-liner for this? Something like

Array3::from_elem(dim.order_of(mask), false)

or anytning that doesn't require an if?

Dominant language
Rust
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