`[const] Destruct` bounds aren't rendered

Tracking issue: #133214

[const] Destruct bounds are rendered as an empty bounds list, which is exposed by some const std functions.

This is not the case for other [const] trait bounds:

#![feature(const_trait_impl)]

pub const trait Foo {}

pub const fn f<T>(_: &T)
where T: [const] Foo {} 

While this is a deliberate choice https://github.com/rust-lang/rust/blob/d29e4783dff30f9526eeba3929ebfe86c00c9dad/src/librustdoc/clean/mod.rs#L229-L234

I think this results in a confusing render, and that it would be better to display it or omit the where T: entirely here

Start in src/librustdoc/clean/mod.rs at the linked lines 229-234, then reproduce the rustdoc output with the provided const-trait examples. Compare the [const] Destruct rendering with the other [const] bound, and consider the issue's two expected outcomes: display the bound or omit the empty where T: clause.