load Rakefile before executing `-p`, `-e`, and `-E` code
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- Dominant language
- Ruby
- Stars
- 2.5k
- Forks
- 650
- Avg merge
- 6m
- Merged PRs (30d)
- 3
Description
Let's say we have this sad little Rakefile:
FOO=23*42
And we want to find out the value of FOO. We look at the --help output, and -p sounds promising:
$ rake --help
...
-p, --execute-print CODE Execute some Ruby code, print the result, then exit.
...
But when we try it...
$ rake -p 'FOO'
rake aborted!
NameError: uninitialized constant Rake::Application::FOO
(See full trace by running task with --trace)
...this is confusing! Especially for a Rake novice.
We can get the result we intended:
$ rake -p 'load_rakefile; FOO'
966
But this requires substantial inner knowledge of Rake.
Suggested behavior:
$ rake -p 'FOO'
966
Thoughts, anyone? Is there a reason I'm missing that -e, -E, and -p don't load the rakefile by default?
Contributor guide
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
Run the documented rake -p 'FOO' reproduction and compare it with rake -p 'load_rakefile; FOO'. Then trace the command-line handling for -p, -e, and -E and how load_rakefile is invoked; done means these options load the Rakefile before evaluating user code and the example prints 966.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- ruby
- Domain
- build-system, cli
- Issue type
- Feature
- Difficulty
- 3/5
- Estimated time
- 1-2 days
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 35/100