riscv-software-src / riscv-software-src/opensbi
Generic heap calculation
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- C
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Description
Perhaps not an issue, but maybe just a request for documentation or comments in the code. The 'generic' machine uses the following formula for heap calculation:
- 0x8000 + (0x1000 * hartcount) + (SBI_TLB_INFO_SIZE * hartcount * hartcount)
What is the reason for the square of the hart count? The reason I'm asking is that for large number of harts, this square factor along with SBI_TLB_INFO_SIZE can become quite large.
Thanks.
Contributor guide
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
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- Open a pull request that references the issue number.
Research direction
Start by locating the generic machine heap calculation and the definition or uses of SBI_TLB_INFO_SIZE. Trace why the hart count is squared, then document that reasoning in the relevant code comments or documentation. Done means the memory requirement and its behavior for large hart counts are clearly explained.
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Assessment
- Tech stack
- c
- Domain
- embedded-iot, operating-systems
- Issue type
- Documentation
- Difficulty
- 3/5
- Estimated time
- 1-2 days
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 38/100