Show source from private modules

Sometimes when I don't want to expose everything in a module, subpackage or whatever I go the following way:

my_package
    __init__.py
    _my_subpackage
        __init__.py
        _my_module.py

Let's say I would like to expose a class from _my_module.py. Then I would do this via exposing the class into _my_subpackage.__init__.py and then into my_package.__init__.py. So I can then use it like this: my_package.MyClass.

So what I want is to just generate api for the top level part where everything is supposed to be public. Therefore I don't use the private-members configuration.
This works in a sense that MyClass can be seen under autoapi/index.html. However I'm missing the very neat [source] button that redirects me to the source where MyClass is implemented, because obviously the file where it's implement is private and therefore nothing get's generated in the build/html/modules/ directory for it.

Is there a workaround for this by chance? 😆 (I know that this is a very specific kind of case)

Reproduce the layout using my_package/init.py, _my_subpackage/init.py, and _my_module.py, then inspect autoapi/index.html and the generated build/html/modules/ output. Trace how the source link for MyClass is generated; done when a publicly exposed class retains a working source link even when its implementation module is private.