in ASL `(void)` doesn't print as `(void)`
Open
Nobody has claimed this yet.
bug
enhancement
- Dominant language
- Racket
- Stars
- 112
- Forks
- 73
- Avg merge
- 9h 41m
- Merged PRs (30d)
- 1
Description
This also manifests itself (I think) as whens not printing anything.
Example:
> (void)
> (when false (void))
> (when true (void))
> (define x 0)
> (when true (set! x 1))
(void)
> (when false (set! x 1))
>
I would expect every line (except the (define x 0)) to print (void).
Contributor guide
No contributing guide indexed for this repository
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
Reproduce the examples in the ASL REPL, focusing on how (void) and when expressions are printed. Trace the relevant ASL evaluation and output path; done means each shown expression except (define x 0) prints (void), including both true and false when cases.
Written by the indexing model from the issue text.
Assessment
- Domain
- cli
- Issue type
- Bug
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 35/100