Incompatible types in assignment (expression has type "bool", variable has type "Literal[False]") with nested code
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Description
To Reproduce
class Bar:
def __init__(self, baz: bool) -> None:
self.baz: bool = baz
def busted(key: int, bar: Bar) -> None:
b = bar
if key > 1:
if b.baz: # No error without this block
return
if key != 1:
baz = b.baz
if key > 0:
if key < 5:
baz = b.baz # error: Incompatible types in assignment (expression has type "bool", variable has type "Literal[False]")
Expected Behavior
This silly example is the smallest I could trim my real code to. It is a lot of nested if that stores references to bool properties in various levels of nesting. At no point is anything else assigned to the local variable (baz in this example).
Actual Behavior
error: Incompatible types in assignment (expression has type "bool", variable has type "Literal[False]")
Your Environment
mypy --version
mypy 0.981 (compiled: yes)
python --version
Python 3.10.6
Mypy command-line flags: None
Contributor guide
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
Start by running the provided nested-if reproduction with mypy 0.981 on Python 3.10.6 and confirm the Literal[False] assignment error. Trace how the checker infers the type of baz across the conditional branches. Done means the valid bool assignment no longer produces this diagnostic, with regression coverage for the example.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- python
- Domain
- compilers
- Issue type
- Bug
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Activity status
- Stale
- Clarity
- Clearly specified
- Newbie friendliness
- 35/100