playframework / playframework/twirl

a String variable with a http url will parse with escaped slash

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#120 1 comment 0 reactions 0 assignees View on GitHub

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status:backlog
Dominant language
Scala
Stars
561
Forks
118
Avg merge
1d 15h
Merged PRs (30d)
29

Description

@(url: String)

@url will parse with escaped slash (/)

like so https:\/\/

Is there any workaround?

Thanks

Pedro

Contributor guide

Open the contributing guide

First steps

  1. Read the whole issue, then the project's contributing guide.
  2. Comment on the issue to say you are picking it up — it saves two people doing the same work.
  3. Fork the repository and make your change on a branch.
  4. Open a pull request that references the issue number.

Research direction

Start by reproducing the reported parsing behavior with the @(url: String) template example and an HTTP URL containing slashes. Trace the Twirl parsing or escaping path to determine the expected output, then add a regression test showing that the rendered URL does not contain escaped slashes.

Written by the indexing model from the issue text.

Assessment

Tech stack
scala
Domain
backend
Issue type
Bug
Difficulty
3/5
Estimated time
1-2 days
Activity status
Stale
Clarity
Needs clarification
Newbie friendliness
35/100

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