Unexpected Result by NATURAL RIGHT JOIN

## Bug Report

The expression `t0.c0 = (t1.c0 NOT LIKE FALSE)` is evaluated to `NULL` for the first query, but returns non-empty result for the second query.

### 1. Minimal reproduce step (Required)

```sql
CREATE TABLE t0(c0 INT);
CREATE TABLE t1(c0 FLOAT);
INSERT IGNORE INTO t0(c0) VALUES (1);
INSERT INTO t1 VALUES (2);
CREATE VIEW v1(c0) AS SELECT 'a' FROM t1;

SELECT t0.c0 = (t1.c0 NOT LIKE FALSE) FROM t1, t0 NATURAL RIGHT JOIN v1; -- {NULL}
SELECT * FROM t1, t0 NATURAL RIGHT JOIN v1 WHERE t0.c0 = (t1.c0 NOT LIKE FALSE); -- {NULL|a}
```

### 2. What did you expect to see? (Required)

### 3. What did you see instead (Required)

### 4. What is your TiDB version? (Required)

```bash
| Release Version: v7.6.0-alpha-347-g598ccada40-dirty
Edition: Community
Git Commit Hash: 598ccada4065e4871bc5bce53a039cbb598a6d82
Git Branch: master
UTC Build Time: 2023-12-01 01:44:42
GoVersion: go1.21.0
Race Enabled: false
Check Table Before Drop: false
Store: unistore |
```