Q: Missing type and simplify generated code

I'm experimenting with code generation based on schemas generated by the glaze C++ library.
The following C++ struct

struct my_struct {
  int i{};
  double d{};
  std::string hello{};
  std::array<uint64_t, 3> arr{};
  std::map<std::string, int> map{};
};

yields this schema:

my_struct.schema.json

And this is the generated rust code.

my_struct.schema.rs.txt

I was wondering the following:

1. Apparently, there is no rust equivalent of my_struct being generated. Instead just for every type inside my_struct. Is there maybe an issue with the schema?
2. Is it somehow possible to prevent generating wrapper types for types like Double etc and just use equivalent types directly?

To demonstrate the latter: I pasted the schema to quicktype and the result seems quite idiomatic:

use serde::{Serialize, Deserialize};
use std::collections::HashMap;

#[derive(Debug, Clone, Serialize, Deserialize)]
pub struct MyStruct {
    arr: Option<Vec<i64>>,
    d: Option<f64>,
    hello: Option<String>,
    i: Option<i64>,
    map: Option<HashMap<String, i64>>,
}

(note: one can get rid of generating all the values as Option by adding "required": ["arr", "d", "hello", "i", "map"], )

Start by reading my_struct.schema.json and my_struct.schema.rs.txt, then compare the generated output with the quicktype example in the issue. Determine how the generator currently represents the schema and what changes would be needed for a my_struct type and direct primitive types; done means the generated Rust matches those requested shapes.