export default function name() {...}
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enhancement
ES6
help wanted
- Dominant language
- C
- Stars
- 1.6k
- Forks
- 239
- Avg merge
- 2d 9h
- Merged PRs (30d)
- 10
Description
now is parsed as named function expression, so the code below does not work:
export default function tropical() {
}
tropical.prototype.sum = function(a, b) {
return a < b ? a : b;
};
tropical.prototype.prod = function(a, b) {
return a + b;
};
tropical.prototype.ZERO = Infinity;
tropical.prototype.ONE = 0;
Contributor guide
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
No source file or test is named in the issue. Start by reproducing the supplied njs example and inspect how export default function tropical() is parsed. Done means the example can use tropical afterward and its prototype methods and constants behave as shown.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- javascript
- Domain
- compilers
- Issue type
- Bug
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 35/100