function object parameter destructure field without default value will be ignored

🔎 Search Terms

js, function, parameter, destructure, required

🕗 Version & Regression Information

• This changed between versions 5.6 and latest nightly
• We use ts 5.5 no this issue, after upgrade this issue occur.

⏯ Playground Link

• ts playground
• stackblitz

💻 Code

// utils.js

export const getUserProfileByUsername = ({
  username,
  withEmail = false,
  withNotificationSettings = false,
} = {}) => {
  return {};
};

// main.ts
import { getUserProfileByUsername } from './utils';

getUserProfileByUsername({
  username: 'ly',
});

🙁 Actual behavior

src/main.ts:4:3 - error TS2353: Object literal may only specify known properties, and 'username' does not exist in type '{ withEmail?: boolean | undefined; withNotificationSettings?: boolean | undefined; }'.

4   username: 'ly',
    ~~~~~~~~


Found 1 error in src/main.ts:4

🙂 Expected behavior

no ts validate error

Additional information about the issue

ts 5.x not this issue, must be introduced by 5.6