templated type alias not recognized

Consider the following code

template<typename T>
struct Foo
{
};

template<typename T> using Bar = Foo<T>;

int main()
{
    Foo<int> foo = {};
    Bar<int> bar = {};
    // break here and hover over foo and bar.
    return 0;
}

with this natvis file

<?xml version="1.0" encoding="utf-8"?>
<AutoVisualizer xmlns="http://schemas.microsoft.com/vstudio/debugger/natvis/2010">
    <Type Name="Foo&lt;*&gt;">
        <DisplayString>this is a Foo</DisplayString>
    </Type>
</AutoVisualizer>

then cppdbg with gcc on Linux will be able to display the content of foo as this is a Foo, but it displays the default visualizer for bar.

Expected result: display this is a Foo for bar as well.

Adding <AlternativeType Name="Bar&lt;*&gt;"> to the Foo type does not work.

Adding a separate <Type Name="Bar&lt;*&gt;"> does not work.

Adding a separate <Type Name="Bar"> does work. However, I loose the information about the template parameters. I can't access $T1 anymore.

Side note / trivia: with cppvsdbg, this is a Foo is displayed for bar - also if the entry for Bar is missing in the natvis file.

More trivia: this contrived example stems from an attempt to display Qt's type QVector which is defined as template <typename T> using QVector = QList<T>.

Reproduce the issue with the templated Foo and Bar example, cppdbg on Linux, and the shown natvis file, then compare visualization of foo and bar. Trace how the natvis Type matching handles the alias and template parameters; done means Bar displays “this is a Foo” while preserving access to the template parameter.