How to "Open with..." program with parameters

I want to open file with program, that uses parameters (e.g. "flatpak run org.videolan.VLC"). But such command cannot be added through app and when I manually edit "Apps (Linux).json" it shows:

Command 'OpenWith' raised error.

Traceback (most recent call last):
  File "fman/impl/plugins/command_registry.py", line 97, in _execute_command
  File "/opt/fman/Plugins/Core/core/commands/__init__.py", line 1906, in __call__
    ShowAppsForOpening(files).show()
  File "/opt/fman/Plugins/Core/core/commands/__init__.py", line 2002, in show
    self.on_selected(option)
  File "/opt/fman/Plugins/Core/core/commands/__init__.py", line 2053, in on_selected
    _open_files_with_app(self._files, option)
  File "/opt/fman/Plugins/Core/core/commands/__init__.py", line 1948, in _open_files_with_app
    Popen(**get_popen_kwargs_for_opening(files, with_=app_path))
  File "subprocess.py", line 676, in __init__
  File "subprocess.py", line 1289, in _execute_child
FileNotFoundError: [Errno 2] No such file or directory: '/usr/bin/flatpak run org.videolan.VLC'

The failure path is in core/commands/init.py, especially _open_files_with_app and get_popen_kwargs_for_opening; start there and inspect how Apps (Linux).json values reach Popen. Reproduce with the flatpak command and verify that an app entry containing parameters can open the selected file without the shown FileNotFoundError.