litesuits / litesuits/android-lite-orm
查询中一对多的问题
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- Dominant language
- Java
- Stars
- 1.5k
- Forks
- 359
- PR merge metrics
- No merged PRs in 30d
Description
查询过程中一对多的问题，我的问题在于一对多过程中的条件筛选
比如说一个老师对应多个学生，学生有出勤、缺勤的这两种状态，我要统计该老师下面出勤学生的数量，该如何进行筛选？
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First steps
- Read the whole issue, then the project's contributing guide.
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Research direction
No file, test, or entry point is identified. Clarify the intended one-to-many filtering behavior and expected result, then locate the relevant LiteOrm query entry point; done means the attendance-filtered student count is reproducible.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- android, java, sqlite
- Domain
- database
- Issue type
- Feature
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Activity status
- Stale
- Clarity
- Needs clarification
- Newbie friendliness
- 20/100