leanprover-community / leanprover-community/mathlib4
Prove that inversion is discontinuous at the center
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Description
- Prove
Tendsto (inversion c R) (𝓝[≠] c) coboundedifR ≠ 0. - Deduce that
inversion c Ris discontinuous atcifR ≠ 0
and the vector space is nontrivial. - Deduce that
fderiv (inversion c R) cis zero, thus
fderiv (inversion c R) x = ((R / dist x c) ^ 2 • (reflection (ℝ ∙ (x - c))ᗮ : F →L[ℝ] F)) x
for allx(see #5937 for the casex ≠ c).
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First steps
- Read the whole issue, then the project's contributing guide.
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Research direction
Read the three unchecked goals in the issue and compare the x ≠ c case in #5937; then identify the existing inversion and fderiv results they build on. Done means all three statements are proved, including discontinuity in a nontrivial vector space and the stated derivative formula.
Written by the indexing model from the issue text.
Assessment
- Domain
- tooling
- Issue type
- Feature
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Activity status
- Quiet
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- Mostly clear
- Newbie friendliness
- 45/100