Suggestion: Add clarification regarding output directory, use "./" for same folder

My problem was that unpacking zipfile 6010.zip using 6010 as output did not work. I got 6010/6010/ and in the latter was the files. Because the archive was a zipped folder named 6010.

Empty string as output, or emitting output completely does not accomplish what I want. Neither finding out the parent directory and using that for output.

Suggestion for this simple clarification in the ReadMe under Output directory.

Add

> Use "./" as output to unpack in the same directory.

> Example:
>
> decompress('unicorn.zip', './').then(files => {
> console.log('done!');
> });
>

Thanks for a great package.

Open the README and find the Output directory section mentioned in the issue. Add the clarification and example showing "./" for unpacking in the same directory; the work is done when the README clearly explains this behavior.

Written by the indexing model from the issue text.