jsumners / jsumners/feedparser
SAXParseException on valid (w3c) rss feed
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Description
What steps will reproduce the problem?
1. feedparser.parse("digitalfernsehen.de/rss/rss91.xml")
2. See SAXParseException('not well-formed (invalid token)')
3. Check
http://validator.w3.org/feed/check.cgi?url=digitalfernsehen.de%2Frss%2Frss91.xml
for valid feed status
What is the expected output? What do you see instead?
Expected ~100 stories with short summaries. Saw exception.
What version of the product are you using? On what operating system?
Using Mac and Ubuntu latest. Python 2.7.
>>> feedparser.__version__
'5.1.2'
Please provide any additional information below.
This is to fix a medium-sized feed in terms of popularity. See
http://www.newsblur.com/site/22353/digital-fernsehen.
Original issue reported on code.google.com by sam...@newsblur.com on 30 Jul 2013 at 10:12
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- Read the whole issue, then the project's contributing guide.
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Research direction
Start by reproducing feedparser.parse("digitalfernsehen.de/rss/rss91.xml") with feedparser 5.1.2 on Python 2.7 and compare the result with the W3C validator status. Done means the valid feed parses without SAXParseException and returns approximately 100 stories with short summaries.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- python
- Domain
- backend
- Issue type
- Bug
- Difficulty
- 3/5
- Estimated time
- 1-2 days
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 35/100