"super" not parse correctly

Steps to reproduce

esprima.parse('!{ a() { !function* (a = super.b()){} } };')

esprima.parse('class a extends b { c() { function* d(c = super.e()){} } }')

esprima.parse('class a extends b { c() { !function* (c = super.d()){} } }')

esprima.parse('function* a(b){ super.c }')

esprima.parse('!function* (a){ super.b }')

esprima.parse('{ a() { function* b(){ super.c(); } } };')

esprima.parse('!{ a() { !function* (){ super.b(); } } };')

esprima.parse('class a extends b { c() { function* d(){ super.e(); } } }')

esprima.parse('class a extends b { c() { !function* (){ super.d(); } } }')

esprima.parse('class a { constructor() { super(); } }')

esprima.parse('class a extends b { static c() { super(); } }')

esprima.parse('class a extends b { constructor() { !{*constructor() { super(); }}; } }')

Expected output

Should throw an error

Actual output

Outputs a AST tree

Start by running the listed esprima.parse reproductions and inspect the parser entry points that handle super expressions, generators, defaults, and class methods. The fix is complete when each invalid example throws an error instead of producing an AST.