Use files from stream instead of parsing the document

I'd love to use something like this:

``` js
gulp.src(['index.html', 'styles/*.css'])
.pipe(if('*.html', inlineCss({
parse: false,
stream: '*.css'
})))
```

Which would just use all CSS files from the stream and it would not parse the template.

Currently I'm trying something like this which of course doesn't work:

``` js
gulp.task('templates', function() {
var assets = useref.assets();

return gulp.src('source/template/*.jade')
.pipe(jade()) // Compile the templates to HTML
.pipe(assets) // Find referenced stylesheets
.pipe(assets.restore()) // Restore HTML file
.pipe(if('*.scss', sass())) // Compile SASS to CSS
.pipe(if('*.html', inlineCss())) // Inline stylesheets
.pipe(gulp.dest('public/')); // Write HTML files to destination
});
```

Basically I want to get referenced SASS files from within the templates, compile them to CSS and apply them to the template using gulp-inline-css without creating temporary files.

Is there any way to do this right now? Would be nice to have this feature and use it as easy as possible!