hsf-training / hsf-training/cpluspluscourse
C++23: `static operator()`
Open
Nobody has claimed this yet.
later
stale
- Dominant language
- TeX
- Stars
- 313
- Forks
- 104
- PR merge metrics
- No merged PRs in 30d
Description
Since C++23, call operators can be declared static, which may lead to better generated code. Also, a lambda's operator() will also be declared static if it does not capture anything.
Contributor guide
No contributing guide indexed for this repository
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
No file, test, or entry point is named. Start by locating the course material covering call operators and lambdas, then determine where C++23 static call operators belong. Done should explain static operator() and the static operator() behavior of captureless lambdas, with suitable course examples if the repository uses them.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- cpp
- Domain
- documentation
- Issue type
- Feature
- Difficulty
- 3/5
- Estimated time
- 1-2 days
- Activity status
- Stale
- Clarity
- Needs clarification
- Newbie friendliness
- 25/100