Tipset throws IndexOutOfBoundsException if the address book becomes smaller

### Description

While reviewing this method:

```
public static Tipset merge(final List tipsets) {
Objects.requireNonNull(tipsets, "tipsets must not be null");
if (tipsets.isEmpty()) {
throw new IllegalArgumentException("Cannot merge an empty list of tipsets");
}

final var firstTipset = tipsets.getFirst();
final int length = firstTipset.tips.length;
final Tipset newTipset = buildEmptyTipset(firstTipset);

for (int index = 0; index < length; index++) {
long max = UNDEFINED;
for (final Tipset tipSet : tipsets) {
max = Math.max(max, tipSet.tips[index]);
}
newTipset.tips[index] = max;
}

return newTipset;
}
```

It appears an IOOBE will be thrown on `Math.max(max, tipSet.tips[index]);` if the address book has become smaller. When merging tipsets, this code takes the first tipset in the list, and uses it for the length. Any subsequent tipset in the merge that is less than this length will not have an index position of "index".

It isn't clear why the first tipset in the list is given preference, or why the new merged tipset should use its length.

### Steps to reproduce

A unit test to this effect has not been written, but could be.

### Additional context

_No response_

### Hedera network

_No response_

### Version

develop

### Operating system

None