Parsec.Expr Example Broken?

Hi!

I'm a wee baby Haskell programmer, but I noticed that the example at the bottom here:

https://hackage.haskell.org/package/parsec-3.1.9/docs/Text-Parsec-Expr.html

Doesn't seem to type check. I don't think the types of parens / reservedOp are agreeing here. Perhaps they changed?

https://hackage.haskell.org/package/parsec-3.1.9/docs/Text-Parsec-Token.html#v:reservedOp

Perhaps the example needs an update, or more clarification?

Thanks!