google-deepmind / google-deepmind/formal-conjectures

Is a finite locally free group scheme killed by its order?

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Description

What is the conjecture

Let $G$ be a finite locally free group scheme of rank $n$ over a base scheme $S$, and let
$[n] : G \to G$ be the $n$-th power map. Lagrange's theorem says that a finite group of order $n$
satisfies $g^n = 1$, and Grothendieck asked whether the same holds for group schemes: does $[n]$
factor through the unit section?

Two cases are known to be affirmative:

  • over a reduced base (SGA 3, Exp. VII$_A$, Prop. 8.5 for a field and Cor. 8.5.2 in general);
  • for commutative $G$ over an arbitrary base, by a theorem of Deligne (1969).

The general case was open for sixty years. It has a negative answer: there is a group scheme of
rank $4$, over a finite non-reduced ring, whose fourth power map is not trivial (its eighth power
map is). The counterexample is in Mathlib as Counterexamples/GrothendieckPower.lean.

What remains open is the refinement: for each $n$, what is the least $m$ such that every finite
locally free group scheme of rank $n$ over every base is killed by $m$? Grothendieck's question
was whether this optimal exponent is $n$; it is not, already for $n = 4$.

Sources:

Prerequisites needed

Everything needed is in Mathlib: HopfAlgebra, the convolution group structure on
WithConv (A →ₐ[R] A) from Mathlib/RingTheory/HopfAlgebra/Convolution.lean, Coalgebra.IsCocomm,
and Module.rankAtStalk together with Module.Finite and Module.Flat.

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First steps

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Research direction

Start with Counterexamples/GrothendieckPower.lean, then read HopfAlgebra, Mathlib/RingTheory/HopfAlgebra/Convolution.lean, Coalgebra.IsCocomm, Module.rankAtStalk, Module.Finite, and Module.Flat. The issue provides the mathematical context and prerequisites, but does not specify a precise formalization target or a completion test.

Written by the indexing model from the issue text.

Assessment

Domain
tooling
Issue type
Feature
Difficulty
5/5
Estimated time
Over a week
Activity status
Active
Clarity
Needs clarification
Newbie friendliness
25/100

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