Infinite Number of Flags

While educating myself on auto-complete, I was poking at `npm` and noticed that their autocomplete scripts allow for an infinite number of flags to be referenced by the completion mechanism, without regard to what position they're in. While the positioning that omelette provides is useful, removing that constraint would also be immensely useful. For reference, here is the script that results from running `$ npm completion`

```bash
###-begin-npm-completion-###
#
# npm command completion script
#
# Installation: npm completion >> ~/.bashrc (or ~/.zshrc)
# Or, maybe: npm completion > /usr/local/etc/bash_completion.d/npm
#

if type complete &>/dev/null; then
_npm_completion () {
local words cword
if type _get_comp_words_by_ref &>/dev/null; then
_get_comp_words_by_ref -n = -n @ -n : -w words -i cword
else
cword="$COMP_CWORD"
words=("${COMP_WORDS[@]}")
fi

local si="$IFS"
IFS=$'\n' COMPREPLY=($(COMP_CWORD="$cword" \
COMP_LINE="$COMP_LINE" \
COMP_POINT="$COMP_POINT" \
npm completion -- "${words[@]}" \
2>/dev/null)) || return $?
IFS="$si"
if type __ltrim_colon_completions &>/dev/null; then
__ltrim_colon_completions "${words[cword]}"
fi
}
complete -o default -F _npm_completion npm
elif type compdef &>/dev/null; then
_npm_completion() {
local si=$IFS
compadd -- $(COMP_CWORD=$((CURRENT-1)) \
COMP_LINE=$BUFFER \
COMP_POINT=0 \
npm completion -- "${words[@]}" \
2>/dev/null)
IFS=$si
}
compdef _npm_completion npm
elif type compctl &>/dev/null; then
_npm_completion () {
local cword line point words si
read -Ac words
read -cn cword
let cword-=1
read -l line
read -ln point
si="$IFS"
IFS=$'\n' reply=($(COMP_CWORD="$cword" \
COMP_LINE="$line" \
COMP_POINT="$point" \
npm completion -- "${words[@]}" \
2>/dev/null)) || return $?
IFS="$si"
}
compctl -K _npm_completion npm
fi
###-end-npm-completion-###
```

Would it be possible to allow the same kind of "as many flags as you want in any position" functionality?