H-Shifts in Conjugated System Tautomerization

## Requirement
The system shall identify a substructure that matches the general configuration:
`H–A–(...)–D`

Where:
- **A** and **D** are terminal heteroatoms from the specific list: Oxygen (O), Nitrogen (N), Sulfur (S), Selenium (Se), or Tellurium (Te).
- `(...)` represents a conjugated system. For the purpose of this rule, a conjugated system is a continuous, unbroken pathway of atoms that allows for electron delocalization. This pathway is formed by either:
- A sequence of alternating single and double bonds between carbon atoms.
- A lone pair of electrons on a heteroatom (N, S, Se, Te, or O⁺) that is adjacent to a double bond in the alternating single-double carbon bond sequence.

Upon identifying a structure that meets these conditions, the system shall allow for the bidirectional interconversion to its corresponding tautomer, `A=(...)=D–H`.

This transformation involves a coordinated rearrangement of the bonds within the conjugated path `(...)`.

This enables proton shifts over distances, such as 1,3-, 1,5-, 1,7-, 1,9-, 1,11-, 1,13-, 1,15-, 1,17-, and 1,19-shifts.

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## Background
This requirement describes the tautomeric migration of a hydrogen atom between two distant heteroatoms. This long-range shift is possible because the conjugated system provides a continuous electronic pathway for the bonds to rearrange.
In both cases, the ability of electrons to delocalize (or move) along this path stabilizes the transition, allowing the proton to migrate.

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## Examples

- **1,3 Shift** (`Rule No PT_06_00`)

- **1,5 Shift** (`Rule No PT_07_00`)

- **1,7 Shift** (`Rule No PT_09_00`)

- **1,9 Shift** (`Rule No PT_10_00`)

- **1,11 Shift** (`Rule No PT_11_00`)

- **1,13 Shift** (`Rule No PT_11_01`)

- **1,15 Shift** (`Rule No PT_11_02`)

- **1,17 Shift** (`Rule No PT_11_03`)

- **1,19 Shift** (`Rule No PT_11_04`)