Can't create an anonymous object with private field

It's not possible to create an anonymous object with a private field in a constructor that already calls the super because in the generated code an abstract class will be generated before the super call.

package foo

import java.util.ArrayList

class Test extends ArrayList<Integer> {

	val Comparable<Integer> a

	new() {
		super() // error here: Java problem: Constructor call must be the first statement in a constructor
		this.a = new Comparable<Integer>() {
			private Integer foo = 5
			override compareTo(Integer i) {
				return foo
			}
		}
		a.compareTo(5)
	}
}

This is however allowed in Java.

package foo;

import java.util.ArrayList;

public class Test extends ArrayList<Integer> {
	private final Comparable<Integer> a;

	public Test() {
		super();
		this.a = new Comparable<Integer>() {
			private Integer foo = 5;

			@Override
			public int compareTo(Integer i) {
				return foo;
			}
		};
		a.compareTo(5);
	}
}

Start with the reproducing source example in the issue and inspect the generated Java for the constructor and anonymous object. Compare its ordering with the valid Java example; done means the example compiles without the super-call error while preserving the private field and its use.