Is it proper to always use std:: on C functions mentioned in examples?

[meta.const.eval] has this code example:

constexpr void f(unsigned char *p, int n) {
  if (std::is_constant_evaluated()) {           // should not be a constexpr if statement
    for (int k = 0; k<n; ++k) p[k] = 0;
  } else {
    memset(p, 0, n);                            // not a core constant expression
  }
}

Should this say std::memset instead of memset to be more consistent with the rest of C++? There are a few other cases in which std:: is omitted for C standard functions.

This is being rather pedantic, because anyone reading the Standard would know what is meant by memset here.

Inspect the [meta.const.eval] example and compare its use of C standard functions with nearby examples in the draft. Check the draft's source conventions for std:: qualification, then update the affected examples if maintainers confirm the preferred style; done means the examples consistently follow the chosen convention.