[module.global.frag] Global namespace has no declaration how could it be "decl-reachable" from a declaration?
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Description
[module.global.frag] p3 says
A declaration D is decl-reachable from a declaration S in the same translation unit if:
- [...]
- there exists a declaration M that is not a namespace-definition for which M is decl-reachable from S and either
- [...]
- D declares a namespace N and M is a member of N, or
The example after this rule has a case that:
template<typename> struct S;
template<typename, int> struct S2;
constexpr int g(int);
template<typename T, int N>
S<S2<T, g(N)>> f(); // S, S2, g, and :: are decl-reachable from f
The declaration M(e.g. S, S2, g) is decl-reachable from S(e.g. f) and is a member of ::, however, :: the global namespace does not have a declaration per [basic.namespace.general] p3
There is a global namespace with no declaration; see [basic.scope.namespace].
The comment is just a bit misleading. It appears to me that the emphasized wording only applies to the namespace that has a namespace-definition.
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Research direction
Start with [module.global.frag] paragraph 3 and the example involving S, S2, g, f, and the global namespace. Compare the decl-reachable wording with [basic.namespace.general] paragraph 3, which states that the global namespace has no declaration. Done means resolving whether the rule or example comment needs clarification.
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Assessment
- Tech stack
- cpp
- Domain
- documentation
- Issue type
- Documentation
- Difficulty
- 3/5
- Estimated time
- 1-2 days
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 42/100