cplusplus / cplusplus/draft

[dcl.constexpr] A full-expression of initialization of a variable may be not an expression CWG3009

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Description

Originally posted by @xmh0511 in https://github.com/cplusplus/draft/issues/4837#issuecomment-908096967 and #4798.

Currently [dcl.constexpr] p10 says that in the defintion of a constexpr variable, the "full-expression of the initialization" shall be a constant expression. And according to [expr.const] p1, a constant expression is also an expression.

However, the "full-expression of the initialization" of a variable may be not an expression. It seems that "full-expression of the initialization" of a variable corresponds to the case specified in [intro.execution] p5 (5.4): an init-declarator (or a mem-initializer) is not an expression.

Note that [expr.const] p2 (2.2) uses "when interpretd as", which may imply that the "full-expression of its initialization" is not itself an expression.

Perhaps there are some contradictions currently, and we should clarify that

  • the full-expression of initialization of a variable is not itself an expression (and hence not a constant expression), and
  • how to "interpret" an initialization as an expression.

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Research direction

Read [dcl.constexpr] p10, [expr.const] p1 and p2 (2.2), and [intro.execution] p5 (5.4), along with the linked issues #4837 and #4798. Determine whether an initialization full-expression is itself an expression and clarify how an initialization is interpreted as an expression, resolving the apparent contradictions.

Written by the indexing model from the issue text.

Assessment

Tech stack
cpp
Domain
documentation
Issue type
Documentation
Difficulty
5/5
Estimated time
Over a week
Activity status
Stale
Clarity
Mostly clear
Newbie friendliness
35/100

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