chakravala / chakravala/Grassmann.jl
Inner Product between vector and bivector
Open
question
- Dominant language
- Julia
- Stars
- 514
- Forks
- 41
- PR merge metrics
- No merged PRs in 30d
Description
Using @basis S"+++"
Define:
x = v1 + v2 + v3
i = v23
when I want the inner product I get x | i = 0, even though I am expecting -v2 + v3. Am I missing something?
Contributor guide
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Research direction
Reproduce the expression in a Julia session using `@basis S"+++"`, `x = v1 + v2 + v3`, and `i = v23`. Read the project's documentation or implementation for the inner-product convention and determine whether `x | i = 0` is intended; document the expected behavior or identify the necessary correction.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- julia
- Domain
- backend
- Issue type
- Bug
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Activity status
- Stale
- Clarity
- Needs clarification
- Newbie friendliness
- 25/100